x2-xy-2y2-x+5y-2
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x2-xy-2y2-x+5y-2
x2-xy-2y2-x+5y-2
x2-xy-2y2-x+5y-2
首先,X^2-XY+2Y^2=(X-2Y)(X+Y)
所以,
设x^2-xy-2y^2-x+5y-2可分解成
(X-2Y+A)(X+Y+B)
则展开有X的一次项=A+B=-1
Y的一次项有A-2B=5
连列成方程,解出A=1 B=-2
所以有原式可以分解为:(X-2Y+1)(X+Y-2)
:(X-2Y+1)(X+Y-2)
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