(sec^2x-sinx+1/x-1/(1+x^2))dx怎么坐
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(sec^2x-sinx+1/x-1/(1+x^2))dx怎么坐
(sec^2x-sinx+1/x-1/(1+x^2))dx
怎么坐
(sec^2x-sinx+1/x-1/(1+x^2))dx怎么坐
原式=∫sec^2xdx-∫sinxdx+∫1/x dx-∫1/(1+x^2) dx
=tanx+cosx+ln|x|-arctanx+C
(sec^2x-sinx+1/x-1/(1+x^2))dx怎么坐
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请解释高数例题:1、求∫sec xdx 2、∫sin√xdx (不知是我错了还是教材错了?)1、求∫sec xdx ∫sec xdx = ∫1/cosx dx=∫cosx/cos^2 x dx=∫dsinx/1-sin^2 x=∫1/2(1/1-sinx + 1/1+sinx)dx=1/2 ln| 1+sinx/1-sinx |+C=1/2 ln(1+s