5x+2y=17.5 8x+4y=32 方程组
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5x+2y=17.5 8x+4y=32 方程组
5x+2y=17.5 8x+4y=32 方程组
5x+2y=17.5 8x+4y=32 方程组
5x+2y=17.5
10x+4y=35 ﹙1﹚
8x+4y=32 ﹙2﹚
﹙1﹚-﹙2﹚, 2x=3
x=1.5
把x=1.5代入8x+4y=32
y=5
∴x=1.5,y=5是原方程组的解
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
x*x+2x+y*y-4y+5=0 x= y=
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x=
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39
初二上学期方程题 4x+y=5 5x+4y=63x-2y=1 2x+3y=13x-2y=7 7x+5y=32x+3y=17 2x-y=-4x+5y=6 2x+y=23x-6y=4 3x+2y=52x+y=73x-4y=53x+y=1x-2y=-1x+y=42x+3y=92x-3y=74x+5y=3x+y=20004x+6y=90003x+5y=113x-2y=42x+3y=215x-2y=5x+y=54x+3y=182x+3y=16x+4y=132x+3y=40x
3(2X+Y)+(2(2x-Y)=6 (8X+4y)-(10X-5Y)=2
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
方程组x-2y=8,3x-4y=5,x=?,y=?
5x+2y=17.5 8x+4y=32 方程组
x+5y+2=0,则4^2x+y*8^y-x