x^2+2y^2+4x-12y+22=0求x,y2x^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 08:46:41
x^2+2y^2+4x-12y+22=0求x,y2x^2
x^2+2y^2+4x-12y+22=0求x,y
2x^2
x^2+2y^2+4x-12y+22=0求x,y2x^2
(x²+4x+4)+2(y²-6y+9)=0
(x+2)²+2(y-3)²=0
因为:(x+2)²≥0、(y-3)²≥0,则:
x+2=0且y-3=0
得:
x=-2、y=3
x^2+2y^2+4x-12y+22=0
(x^2+4x+4)+2(y^2-6y+9)=0
(x+2)^2+2(y-3)^2=0
所以x=-2,y=3
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值
(X,Y) f(x,y)={12y^2,0
x*x+2x+y*y-4y+5=0 x= y=
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
X×X-2XY-Y×Y+2X-2Y+2=02X×2X-4XY-2Y×2Y+3X-3Y+4=0X×X+2XY+Y×Y+X+Y-56=0X×X-2XY+Y×Y-X+Y-12=0X×X-3XY+Y×Y=-13X×3X-XY+3Y×3Y=13 两个在一起的方程之间有所联系(要求一步一步写出来)
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
{x+y+z=12 x+2y+5z=22 x=4y
求x ,y 9x^2+4y^2-12x-8y+8=0
x²+4y²-2x+12y+10=0求X,Y值
若x.y满足条件2x+y-12=0,x-4y+10
(x-4y)(2x+y)=
先化简再求值; 解方程组 x(x-y)-y(x+y)+2xy 其中x=2 ,y=-22.x[x-x(x-1)],其中x=-2解方程组4x+3y=12x-y=32.y+1=2x 4x-y=2 3.2x+2y=0 2x-y+24=0
求x²+y²-2x+4y+1的最小值 求x,y的值 x²+2xy+4x-12y+22=0
x^2+2y^2+4x-12y+22=0求x,y2x^2
x*x+y*y-2x+4y+5=0求x,