已知log(2)3=a,log(3)7=b试用a,b表示log(2)14

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已知log(2)3=a,log(3)7=b试用a,b表示log(2)14
已知log(2)3=a,log(3)7=b试用a,b表示log(2)14

已知log(2)3=a,log(3)7=b试用a,b表示log(2)14
log(2)3=a,log(3)7=b
所以,log(2)7=ab
1+log(2)7=ab+1
log(2)2+log(2)7=ab+1
log(2)(2×7)=ab+1
log(2)14=ab+1

log(2)14=log(2)7+log(2)2=log(2)7+1
log(3)7=log(2)7/log(2)3
log(2)7=log(3)7 log(2)3=ab
log(2)14=ab+1

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