(7x^2y^3-8x^3y^2z)/8x^2y^2计算

{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 解三元一次方程：x+y-z=0,2x+y+z=7,x-3y+z=8 解方程组x+y-z=0,2x+y+z=7,x-3y+z=8 {x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2 X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z= 已知:x+y+z=0,5x-3y-z=0,求:5x-y+z/2x+8y+7z 的值 (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian 2x-{3z-[3x-2(z-y)-(x+8y-6z)]} x+y+z=1 x+3y+7z=-1 x+5y+8=2题错了 x+y+z=1 x+3y+7z=-1 x+5y+8z=2 12x^2y^3z-8x^3y^2z+4x^2y 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 三元一次方程组2x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=262x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=26 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊