if(s->s>a[i].s)可以换成if(*s.s>a[i].#include#include#include#include#define N 10typedef struct ss{ char num[10]; int s;} STU;fun(STU a[],STU *s){int i;*s=a[0]; /*先认为第1个值最小*/for(i=0;is>a[i].s)*s=a[i];}void main(){ FILE *wf;STU a[N]

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if(s->s>a[i].s)可以换成if(*s.s>a[i].#include#include#include#include#define N 10typedef struct ss{ char num[10]; int s;} STU;fun(STU a[],STU *s){int i;*s=a[0]; /*先认为第1个值最小*/for(i=0;is>a[i].s)*s=a[i];}void main(){ FILE *wf;STU a[N]
if(s->s>a[i].s)可以换成if(*s.s>a[i].
#include
#include
#include
#include
#define N 10
typedef struct ss
{ char num[10];
int s;
} STU;
fun(STU a[],STU *s)
{
int i;
*s=a[0]; /*先认为第1个值最小*/
for(i=0;is>a[i].s)
*s=a[i];
}
void main()
{
FILE *wf;
STU a[N]={{ "A01",81},{ "A02",89},{ "A03",66},{ "A04",87},{ "A05",77},
{ "A06",90},{ "A07",79},{ "A08",61},{ "A09",80},{ "A10",71}},m;
int i;
system("CLS");
printf("/
}

if(s->s>a[i].s)可以换成if(*s.s>a[i].#include#include#include#include#define N 10typedef struct ss{ char num[10]; int s;} STU;fun(STU a[],STU *s){int i;*s=a[0]; /*先认为第1个值最小*/for(i=0;is>a[i].s)*s=a[i];}void main(){ FILE *wf;STU a[N]
A

a

if(s[i]>=‘a’&&s[i] if(s->s>a[i].s)可以换成if(*s.s>a[i].#include#include#include#include#define N 10typedef struct ss{ char num[10]; int s;} STU;fun(STU a[],STU *s){int i;*s=a[0]; /*先认为第1个值最小*/for(i=0;is>a[i].s)*s=a[i];}void main(){ FILE *wf;STU a[N] what's the matter i have a cold.可以把问句换成what‘s your matter if(s[i]>='0'&&s[i] It's just a job.For me ,it's what I love.这里的what可以换成which吗? if(s->s>a[i].s)其中的减号什么意思 if(s[i]!=s[n-i-1])这个是什么意思 it's as if I play a part I”s If it's all ever i 下面的表达式哪个是正确的?A String s=你好;int i=3; s+=i; B String s=你好;int i=3; if(i==s){s+=i}; C String s=你好;int i=3; s=i+s; D String s=你好;int i=3; s=i+; E.String s=null; inti=(s!=null)&&(s.length>0)?s.length():0; ja s i i n s t可以组成什么单词 请教这句话的意思：I wonder if he’s taken.hottie n.a sexually attractive person.-He’s a real hottie!I wonder if he’s taken. s u i b i c t 可以组成什么食物单词a s a u e g s呢 lt i s a secret s( )les a( )( )i( )( )ant She's got a headache.(将She换成I）,怎么办 if(i%7)s+=i；这句话是什么意思?