化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-x)+z^3(x-y)]=是y^3.正确的是化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^3(z-x)+z^3(x-y)]=
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化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-x)+z^3(x-y)]=是y^3.正确的是化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^3(z-x)+z^3(x-y)]=
化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-x)+z^3(x-y)]=
是y^3.
正确的是化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^3(z-x)+z^3(x-y)]=
化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-x)+z^3(x-y)]=是y^3.正确的是化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^3(z-x)+z^3(x-y)]=
貌似分母的倒数第二项应该是y^3吧.
分子拆括号再提取公因式得(xy)^2(x-y)+(xz)^2(z-x)+(yz)^2(y-z)
分母拆括号再提取公因式得(xy)(x+y)(x-y)+(xz)(z+x)(z-x)+(yz)(y+z)(y-z)
小朋友。。 自己慢慢算撒 靠网络帮你学习是不行滴
(xy)^2(x-y)+(xz)^2(z-x)+(yz)^2(y-z)
(xy)(x+y)(x-y)+(xz)(z+x)(z-x)+(yz)(y+z)(y-z)
化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z}
2(x+y)(x+y-z)+3(y-z)(x+y-z)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
(x-3y+2z)(x+3y-2z)
(x-2y+3z)(x+2y-3z)
(2y-x-3z)(-x-2y-3z)
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-x)+z^3(x-y)]=是y^3.正确的是化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^3(z-x)+z^3(x-y)]=
(x+3y-2z)(x-3y-2z)-(x+3y-2z)^2
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z)
若x+y+z=3y=2z,则x/x+y+z=?
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)