作业帮log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)说明)-lg4-2lg5怎么算
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log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)说明)-lg4-2lg5怎么算
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)
说明)-lg4-2lg5怎么算
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)说明)-lg4-2lg5怎么算
-lg4-2lg5
=-(lg4+lg25)
=-[lg(4×25)]
=-lg100
=-2
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)
=(2lg3)/(3lg2) × (5lg2)/(lg3) - (lg4+lg25) +3 +9
=10/3 - 2+12
=40/3
计算log8底9*log3底32
log3(2)*log8(9)
lg(1/2)-lg(5/8)+lg12.5-log8＾9×log3＾4要过程
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)说明)-lg4-2lg5怎么算
已知log8^9=a log3^5=b 求lg 2
(9/4)^(-1/2)+log8 9*log3 32=
以8为底9的对数乘以3为底2的对数?log8^9*log3^2=?
计算 lg1∕2-lg1∕8+lg12.5-log8为底9乘以log3为底4
关于数学对数中换底公式的问题.求log8^9 * log3^32的值.
已知log8 3=a,log3 5=b,求lg 5
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log3（2）*log8（9）怎么计算?
log8 9*log3 2+lg5lg20+(lg2)^2=?
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求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?..
log8^9乘以log3^2的值为 A 2/3 B 1 C 3/2 D 2,求具体过程,
log8^9*log27^32