作业帮dy/dx+(2/x)y=-x当y(2)=0时,
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dy/dx+(2/x)y=-x当y(2)=0时,
dy/dx+(2/x)y=-x当y(2)=0时,
dy/dx+(2/x)y=-x当y(2)=0时,
y'+2y/x=－x,
xy'+2y=－x^2,
x^2*y'+2xy＝－x^3,
(x^2y)'＝－(x^4/4)',于是
x^2y＝－x^4/4+C,利用y(2)=0得
C＝2^4/4=4.故解为
y＝(4－x^4/4)/x^2
＝4/x^2－x^2/4.
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