计算(1)(√a+√b)²(a≥0,b≥0)

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计算(1)(√a+√b)²(a≥0,b≥0)
计算(1)(√a+√b)²(a≥0,b≥0)

计算(1)(√a+√b)²(a≥0,b≥0)
(√a+√b)²
=(√a)+2(√a)(√b)+(√b)²
=a+2√(ab)+b

a+b+2根号的ab

(1)(√a+√b)²
=a+2(√a*√b)+b
=a+2√(ab)+b