lim(x-->0)(√(1-2x-x^2)-(1-x))/x
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lim(x-->0)(√(1-2x-x^2)-(1-x))/x
lim(x-->0)(√(1-2x-x^2)-(1-x))/x
lim(x-->0)(√(1-2x-x^2)-(1-x))/x
上下乘√(1-2x-x^2)+(1-x)
分子是平方差
所以原式=lim(1-2x-x²-1+2x-x²)/x[√(1-2x-x^2)+(1-x)]
=-2limx/[√(1-2x-x^2)+(1-x)]
=0
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