3X-2Y=4 5X+3Y-13=0 这个方程组怎样解
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3X-2Y=4 5X+3Y-13=0 这个方程组怎样解
3X-2Y=4 5X+3Y-13=0 这个方程组怎样解
3X-2Y=4 5X+3Y-13=0 这个方程组怎样解
3x-2y=4 ( 标注)1
5x+3y-13=0 (标注)2
化简2得,5x+3y=13(标注)3
由1得x=(4+2y)/3(标注4)
把4代入3,得5[(4+2y)/3]+3y=13
19/3y=19/3
y=1
把y=1代入3得 x=2
所以{x=2
{y=1
3X-2Y=4 Y=(3X-4)/2
5X+3Y=13 Y=(13-5X)/3
Y=Y
3(3X-4)=2(13-5X)
X=2 Y=1
3X-2Y=4
X+3Y=13
11Y=35
Y=35/11
X=38/11
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
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