|x-3|-|x+1|>3怎么算
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|x-3|-|x+1|>3怎么算
|x-3|-|x+1|>3怎么算
|x-3|-|x+1|>3怎么算
当x=0,x+1>0,所以原式化为x-3-(x+1)>3,即-4>3,该式不可能成立;
综上所述,可得x的取值范围为x
我交你三种算法,你把QQ号给我。我写好用图片发给你,以后遇到这题不会犯困了
x<-1/2
x≥3时,原式=-4<0,
-1≤x≤3时,3-x-x-1>3
∴-1≤x<-1/2
x<-1时,原式=4>3
∴x<-1
综上之,x<-1/2
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