将(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²用提公因式法分解因式.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/01 17:02:19
将(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²用提公因式法分解因式.
将(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²用提公因式法分解因式.
将(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²用提公因式法分解因式.
提公因式=(z-x-y)² (x+y-z)²=(z-x-y)²
(x+y-z)²(x+y+z-y-z+x)=(x+y-z)²*2x
=(x+y-z)²(x+y+z)-(y+z-x)(x+y-z)²=(x+y-z)²(x+y+z-y-z+x)=2x(x+y-z)²
(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²=(x+y-z)²(x+y+z-y-z+x)=(x+y-z)²*2x
(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²
解:原式=(x+y-z)²(x+y-z)²(z-x+y)(z-x-y)
=(x+y-z)²²
四次方大不出来,用两个平方代替
因式分解 (x-y+z)²(x+y-z)²
(x+y+z)²-(x-y-z)²
运用公式法:将下列多项式是因式分解:(x+y+z)²-(x-y-z)²
因式分解(x-y+z)² -(x+y-z)²因式分解(x-y+z)² -(x+y-z)²
(x-2y+z)²
将(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²用提公因式法分解因式.
因式分解:(x-z)²+4(y-x)(y-z)kuai
将下列式子因式分解(不需过程,将答案表述清楚就行)x²y-y²z+z²x-x²z+y²x+z²y-2xyz
x²y-y²z+z²x-x²z+y²x+z²y-2xyz因式分解结果是?
因式分解:x²y-y²z+z²x-x²z+y²x+z²y-2xyzkuai
1998(z-y)+1999(y-z)+2000(z-x)=0 1998²(z-y)+1999²(y-z)+2000²(z-x)=0求z-y的值1998(x-y)+1999(y-z)+2000(z-x)=0 1998²(x-y)+1999²(y-z)+2000²(z-x)=0求z-y的值
计算:(x-2y+z)²
因式分解:x²-y²-z²+2yz
因式分解 x²-2xy+y²-z²
16x²y²z²-9分解因式
分解因式 16x²y²z²-9
一道数奥题,(x+y-z)²+(y+z-4)=-|z+x-5|
设x,y,z∈,R求证:x²+xz+z²+3y(X+y+z)≥0