★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ] + tanθ (.)

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/08 06:42:30

★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ] + tanθ (.)
★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ] + tanθ (.)

★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ] + tanθ (.)
f'（x）=sinθx²+√3cosθx
f'（1）=sinθ+√3cosθ=（1/2）×sin（θ+π/6）
θ∈[0,5π/12],则θ+π/6∈[π/6,7π/12].
∴θ+π/6=π/2,即θ=π/3时,f'（1）有最大值1/2.
θ+π/6=π/6,即θ=0时,f'（1）有最小值0.
综上,f'（1）的取值范围是[0,1/2].

设函数f(x)=-x^2+x+7,若不等式f(3+2sinθ) 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+∮)(-兀 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 1.设函数f(x)=sin(x+fai)(0 设函数f(x)=sin(2x+φ)(-π ★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ] + tanθ (.) 设函数f(x)=sin(wx+t)(-π/2