#define S(x) 3

#define s(x) 3 #define S(x) 3 若有宏定义# define s(x) x*x-x,设int k=3; 问cout 3．设有以下程序：、#include #define S(X) X*Xvoid main(void){int k=2；cout #include #define S(x) x*x main() {int a=9,k=3,m=2; a/=S(k+m)/S(k+m); print(%d,a); #include #define S(x) x*x void main() { int a,k=3,m=1; a=S(k+m); printf(%d,a);} #define S(x) 4*(x)*x+1 s(4)怎么计算 define fun(x, #define configASSERT( x ) #define F(x) x - 2 #define D(x) x*F(x) printf(%d,%d,D(3),D(D(3))) ; #define X 3 #define Y X*2 #undef X #define X 2 int z=Y; z 的值为多少? #define N 10#define s(x) x*x#define f(x) (x*x)main(){int i1,i2;i1=1000/s(N);i2=1000/f(N);printf(%d %d ,i1,i2);}运行结果是? 这俩题的答案是几,怎么算的?第一题：#define N 3#define Y（n） （（N+1）*n）则执行语句：z=2*（N+Y（5+1));后,z的值为——第二题：#include #define PT 5.5#define S(X) PT*X*Xvoid main(){int a=1,b=2;printf(%4.1f/n,S(a #define f(x) x*x*x main() { int a=3,s,t; s=f(a+1);t=f((a+1)); printf(%d,%d,s,t)；为啥输出是10,64 #define f(x) x*x*x main() { int a=3,s,t; s=f(a+1);t=f((a+1)); printf(%d,%d ,s,t); } 程序运行结果 #define min(x,y) (x #define MIN(x,y)(x) #define __T(x) L ## x