4-m^2/(m+4)^2÷m-2/2m+8×m-2/m+2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 07:54:18
4-m^2/(m+4)^2÷m-2/2m+8×m-2/m+2
4-m^2/(m+4)^2÷m-2/2m+8×m-2/m+2
4-m^2/(m+4)^2÷m-2/2m+8×m-2/m+2
原式=(4-m)(4+m)/(4+m)^2*2(m+4)/(m-4)*(m-2)/(m+2)=-2*(m-2)/(m+2) =4-2m/m+2很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
计算:(m+3m+5m+...+2009m)-(2m+4m+6m+...+2008m)
(m+3m+5m+...+2009m)-(2m+4m+6m+...2008m)
(m+3m+5m+...+2014m)-(2m+4m+6m+...+2013m)
(m+3m+5m+...+2013m)-(2m+4m+6m+...+2012m)
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
计算:(m+3m+5m+...+2009m)-(2m+4m+6m+...+2010m)
m-2m-3m+4m-5m-6m+7m.2004m=?
(m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=?
化简(m*m-2m)/(4-m*m)
4-m^2/(m+4)^2÷m-2/2m+8×m-2/m+2
化简:【2m/(m+2) - m/(m-2)】÷m/(m²-4)
m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m求m的值
(m+3m+5m+...+2009m)-(2m+4m+...+2008m)怎么算
合并同类项m-2m+3m-4m+5m-.+2011m-2012m
m+3m+5m+...+2011m-2m-4m-...-2010m等于多少?
已知m>4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3|
计算(m+3m+5m+7m+.+2009m)-(2m+4m+6m+.+2008m)
计算(m+3m+5m+7m+.+2013m)-(2m+4m+6m+.+2012m)