化简cos^4α/6-sin^4α/6

sin^6а+cos^6а+3sin²аcos²а化简=(sin^2α+cos^2α)(sin^4α-sin^2α*cos^2α+cos^4α)+3sin^2α*cos^2α这一步的sin四次方是怎么出来的?看不懂,求这一步的详写. 化简cos^4α/6-sin^4α/6 1-cos^6（α）-sin^6(α)/1-cos^4(α)-sin^4(α) [1-（sinα）^4-(cosα)^4]/[1-(sinα)^6-(cos)^6)]=? 2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)mingbaidian 2(sin^6 α +cos^6α)-3(sin^4a+cos^4α) 化简：（1）sin^2·α+cos^4·α+sin^2·αcos^2·α（2）（1-cos^4·α-sin^4·α）/(1-cos^6·α-sin^4·α) 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= 若sinα+sin^2α=1,则cos^2α+cos^4α+cos^6α=? 1.化简根号2cos x - 根号6sin x2.已知sin(α-β)cosα-cos(β-α)sinα=3/5,β是第三象限角,求sin(β+5π/4)的值.3.化简sin(α-β)sin(β-λ)-cos(α-β)cos(λ-β) 化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x) 求证!快 sin^2α/（1+cotα)+cos^2α/（1+tanα)=1-sinαcosα第一题 sin^2α/（1+cotα)+cos^2α/（1+tanα)=1-sinαcosα第二题 tanαsina/(tanα-sina)=(tanα+sinα)/tanαsinα第三题 化简 (1-sin^4α-cos^4α)/(1-sina^6α-cos^6α) 1.化简：（1-sin^6α -cos^6α)/(1-sin^4α -cos^4α)2.α为三角形内角,lg(sinα + cosα)=1/2lg5 -lg3,求sinα - cosα,tanα的值.3.已知：log(tanα)(cosα)=2/3 (0＜α＜π/2),求证:log(1+cot^2α)(sinα*cosα)=-7/10.4.已知：5sinβ=sin（ 数学三角函数 sinα+2cosα=1/6 求sinα-4cosαsinα+2cosα=1/6 求sinα-4cosα 要求详细过称和结果 急 化简sinα^6+cosα^6+3sinα^2cosα^2的结果是 化简：sin^6α+cos^6α+3sin^2α*cos^2α=? 化简sin^4α+cos^4α+2sin^2α*cos^2α-1