若x^2+y^2+6x-8y+25=0,求y^x的值
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若x^2+y^2+6x-8y+25=0,求y^x的值
若x^2+y^2+6x-8y+25=0,求y^x的值
若x^2+y^2+6x-8y+25=0,求y^x的值
(x+3)^2+(y-4)^2=0
x=-3 y=4
y^x=1/64
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若x^2+y^2+6x-8y+25=0,求y^x的值
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8