(y+1)^2dy/dx+x^3=0 求通解

x^2+xy+y^3=1,求dy/dx 求下列微分方程的通解,对于有初始条件的,1、dy/dx+y=e^-x2、dy/dx-2y/x+1=(x+1)^33、x*dy/dx+y=3,y(1)=0可+分 y^2+xy+3x=9求：dy/dx,于是得到2y dy/dx+1 y+dy/dx+3=0,我不明白怎将y看成x的函数? Y=2-sinx.求dy/dx及dy/dx|x=0 求方程 dy/dx+x(y-x) +x^3(y-x)^2=1的通解~ 3x^2+4y^2-1=0,求dy/dx (y+1)^2dy/dx+x^3=0 求通解 求[(y+1)^2]dy/dx+x^3=0的通解! (1-x)dx-(1+y)dy=0求通解 求dy/dx-(x-1)/y=0的解 求dx+(x+y^2)dy=0的通解 y=Insin(3x-1),求dx分之dy 设y=√(x^2-1)求dy/dx 求dy/dx-2y/x=1的通解 设y=sin2x/(1+x^2),求dy/dx, 设y=sin2x/(1+x^2),求dy/dx, 求dy/dx y=e^(2x+1) y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy