tan(π-π/6)=tan(5π/6)=-tanπ/6=-√3/3,正确否?
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tan(π-π/6)=tan(5π/6)=-tanπ/6=-√3/3,正确否?
tan(π-π/6)=tan(5π/6)=-tanπ/6=-√3/3,正确否?
tan(π-π/6)=tan(5π/6)=-tanπ/6=-√3/3,正确否?
正确的.
tanα=2则tan(α-π/6)=5根号3-8,
tan(-23π/6)=
tan(π/6-α)+tan(π/6+α)+√3tan(π/6-α)tan(π/6+α)=?
tan(π-π/6)=tan(5π/6)=-tanπ/6=-√3/3,正确否?
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