sinx>sin(2π/3-x)（0

sinx>sin(2π/3-x)（0 f(x)=2sinx*sin(x+π/3) 化简 求X解集：sinx=2sin(π/3-x) lim(1+sinx-sin(sinx))^x^-3 x趋于0 证明x∈(0,π/2),cos(cosx)>sin(sinx) 解方程：sinx=2sin(π/3-x) |sin(x+π/2)|-|sinx|求导过程? sinx+cosx/sinx-cosx=2,则sin(x-5π)sin(3π/2-x)=? 3sinx-2cosx=0 (1)(cosx-sinx)/(cosx+sinx)+(cosx+sinx)/(cosx-sinx) (2)sin^2 x-2sinxcosx+4cos^2 x 化简：（sinx）^2+(sin（x+π/3))^2+(sin(x+2π/3))^2 sinx+sin(x+2/3π)+sin(x-2/3π) 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 已知2sin平方x-3sinxcosx+cos平方=0 求(cosx-sinx)/(cosx+sinx) S(1-sin^2x)d(sinx)为什么=sinx-1/3sin^3x? ∫（0,π/2）sinx/(3+sin^2x)dx求定积分 求定积分（0到π／2）sin^3x／（sinx+cosx）dx=? 定积分∫(sinx+sin^3(x))^1/2 [上限为π下限为0] 表示出sin的反三角函数 sinx=-2/3 x属于(-π,0)