已知实数x.y.z满足x+y=5及z的2次方=xy+y-9则x+2y+3z=?

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已知实数x.y.z满足x+y=5及z的2次方=xy+y-9则x+2y+3z=?
已知实数x.y.z满足x+y=5及z的2次方=xy+y-9则x+2y+3z=?

已知实数x.y.z满足x+y=5及z的2次方=xy+y-9则x+2y+3z=?
x=5-y
z2=(5-y)y+y-9
=6y-y2-9
=-(9-6y+y2)
=-(y-3)2
由题意,只有当该项为0时等式成立
得y=3
那么z=0 x=2
即原式=2+6+0=8

x+2y+3z=5+y+3z;
z^2=6y-y^2-9=-(y-3)^2;
-(y-3)^2>=0
故z=0,y=3,x=2
x+2y+3z=8