为什么1/(cost(cost-1))可以变成1/cost-1/(cost-1),
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为什么1/(cost(cost-1))可以变成1/cost-1/(cost-1),
为什么1/(cost(cost-1))可以变成1/cost-1/(cost-1),
为什么1/(cost(cost-1))可以变成1/cost-1/(cost-1),
因为分母相差1.所以1/cost 减去1/(cost-1)=1/(cost(cost-1))
类似的规律有,若1/ab,且ab相差n.并且a
为什么1/(cost(cost-1))可以变成1/cost-1/(cost-1),
1/cost的不定积分
∫dt/(1+cost)
sint/(1-cost)求导
(cost-sint)/(sint-cost) 的结果不知道等不等于 -(sint-cost)/(sint-cost)也就是-1
t趋于0时为什么lim(sint+cost-1)/t=lim(cost-sint)=1)
sint/(1-cost)=cost/2怎么推?
∫dt/(1+sint+cost)
sint/1-cost=什么
t/(1+cost)的不定积分
为什么sint/(1-cost)=cot(t/2)
因为t趋于0时,lim(sint cost-1)/t=lim(cost-sint)=1这是为什么
t趋于0时lim(sint+cost-1)/t=lim(cost-sint)=1)t趋于0时为什么lim(sint+cost-1)/t=lim(cost-sint)=1)
1/(1 cost)的不定积分怎么求
(1/(1+sint+cost))dt不定积分
求积分 ∫ [ 1 / (cost)^3 ]dt
此参数方程为什么这么解x=2(t-cost)y=2(1-sint)求dy/dx.答案是dy/dx = -cost/(1+sint)为什么dx= 2(1+sint)dt为什么dy= -2cost
do does ; cost costs的用法!1:how much do the carrots cost?the carrots cost three dollars.2:how much does the tea cost?the tea costs two euros.3:how much does a movie ticket cost?a movie ticket costs nine pounds.问:为什么第一句用d