若2x减3y=5,则6-4x+6y=?
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若2x减3y=5,则6-4x+6y=?
若2x减3y=5,则6-4x+6y=?
若2x减3y=5,则6-4x+6y=?
6-4x+6y
=6-2(2x-3y)
=6-2×5
=-4
6-4x+6y
=6-(4x-6y)
=6-2(2x-3y)
=6-2×5
=6-10
=-4
若5x+3y=3x+4y=x+2y+6,则x+y=___
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
若2x减3y=5,则6-4x+6y=?
把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
把(x-y)看做一个整体,合并同类项5(x-y)+2(x-y)-4(x-y)=3(x-y)次方-4(x-y)+7(x-y)-6(x-y)次方=
若|5x+2y-12|+(3x+2y-6)(3x+2y-6)=0,则2x+4y=
4x-2y-6y*-y-3x+5y* *=2 就是平方
若(5X+2Y-12)(5X+2Y-12)+|3x+2y-6|=0,则2x+4y=?