解方程:1-(4÷[(1-X)(1+X)])=(X-3)÷(X-1)

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解方程:1-(4÷[(1-X)(1+X)])=(X-3)÷(X-1)
解方程:1-(4÷[(1-X)(1+X)])=(X-3)÷(X-1)

解方程:1-(4÷[(1-X)(1+X)])=(X-3)÷(X-1)
原方程可化为:
1+ 4÷[(x-1)(x+1)]=(x-3)÷(x-1)
两边同乘以(x-1)(x+1)可得:
(x-1)(x+1)+ 4=(x-3)(x+1)
即:x²-1+4=x²-2x-3
移项整理得:2x=-6
解得:x=-3
经检验,原方程的解为:x=-3

1-4/(1-X)(1+X)=(X-3)÷(X-1)
(x-1)+4/(1+x)=(X-3)
(x-1)(x+1)+4=(X-3)(x+1)
x²+4=x²-2x-3
2x=-7
x=-7/2

1-(4÷[(1-X)(1+X)])=(X-3)÷(X-1)可得:(1-X)(1+X)≠0,X-1≠0即x≠1且x≠-1
化简方程:(-x²-3)/[(1-X)(1+X)]=(X-3)/(X-1)
(x²+3)/(x+1)=x-3 即:x²+3=x²-2x-3 得出 x=-3

1-(4÷[(1-X)(1+X)])=(X-3)÷(X-1)
1-4/(1-x)^2=(x-3)/(x-1)
(1-x^2-4)/(x^2-1)=(x-3)/(x-1)
(x^2+3)/(x^2-1)=(x-3)/(x-1)
(x^2+3)/(x+1)=(x-3)
x^2+3=(x-3)(x+1)
x^2+3=x^2-2x-3
x=-6