初二4道因式分解题,求解!(1)4/9p²q²-1(2)25(m+n)²-9n²(3)4a³-4a²+a(4)(x-1)(x-3)+1请附上至少一步的过程,万分感谢!

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初二4道因式分解题,求解!(1)4/9p²q²-1(2)25(m+n)²-9n²(3)4a³-4a²+a(4)(x-1)(x-3)+1请附上至少一步的过程,万分感谢!
初二4道因式分解题,求解!
(1)4/9p²q²-1
(2)25(m+n)²-9n²
(3)4a³-4a²+a
(4)(x-1)(x-3)+1
请附上至少一步的过程,万分感谢!

初二4道因式分解题,求解!(1)4/9p²q²-1(2)25(m+n)²-9n²(3)4a³-4a²+a(4)(x-1)(x-3)+1请附上至少一步的过程,万分感谢!
1)4/9p²q²-1
=(2/3pq-1)(2/3pq+1)
(2)25(m+n)²-9n²
=[2(m+n)+3n][2(m+n)-3n]
=(2m+2n+3n)(2m+2n-3n)
=(2m+5n)(2m-n)
(3)4a³-4a²+a
=a(4a²-4a+1)
=a(2a-1)²
(4)(x-1)(x-3)+1
=x²-4x+3+1
=x²-4x+4
=(x-2)²

1.=(2/3pq)^2-1
=(2/3pq-1)(2/3pq+1)
2.=[5(m+n)]^2-(3n)^2
=(5m+5n+3n)(5m+5n-3n)
=(5m+8n)(5m+2n)
3.=a(4a^2-4a+1)
=a(2a-1)^2
4=x^2-4x+3+1
=x^2-4x+4
=(x-2)^2