解不等式7-x/x-3>1

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解不等式7-x/x-3>1
解不等式7-x/x-3>1

解不等式7-x/x-3>1
7-x/x-3>1

[(7-x)-(x-3)]/(x-3)=(10-2x)(x-3)>0
所以:2(x-5)/(x-3)

(7-x)/(x-3)>1 移项
(7-x)/(x-3)-1>0 通分
(7-x-x+3)/(x-3)>0
(10-2x)/(x-3)>0
(2x-10)/(x-3)﹤0
(x-5)/(x-3)﹤0
所以
3﹤x﹤5
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