log(2)3,0.5^-1,4^(-3/2),log(0.5)3,大小关系

(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题. 4^[log(2)3+log(4)8] log(2)9log(3)4等于 log(2)9×log(3)4 已知lg2=0.301,lg3=0.477,求（1）log(2)1000,(2)log(5)0.5,(3)log(9)8,(4)log(1/2)1/3 log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) log(1/2)3,log(1/3)3,log(1/4)3比大小 2^log(4)(3)加3^log(9)(1/4)加5^log(1/25)(2) 1、log下标3 2(log下标4 3+log下标8 3)2、log下标1/3 √27+log下标27 1/3 计算：（1） log(2)(3)*log(3)(4)*log(4)(5)（2）log(2)(7)*log(√7)(8) log(2)3,0.5^-1,4^(-3/2),log(0.5)3,大小关系 化简:(log^3 2+log^9 2)(log^4 3+log^8 3) (log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路 (log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路 化简log(2)3 * log(3)4 * log(4)7 *log(7)16 log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃.... 求大神指点,lingo出现错误代码11,这是为什么?model:!目标函数;min=(0.005*((@log(1+k))^2+(@log(1+2*k))^2+(@log(1+3*k))^2+(@log(1+4*k))^2+(@log(1+5*k))^2))!/(@log(1+k)+@log(1+2*k)+@log(1+3*k)+@log(1+4*k)+@log(1+5*k));!约束条件;(@log [log(4)3+log(8)3][log(3)2+log(9)2]-log(1/2)32∧1/4过程详细点,log(4)3是log以4为底3的对数，