matlab a=[pi/6 pi/4;pi/3 3*pi/4]; funm(a,'sin') ans= 0.1864 0.0764 0.1018 0.3646 怎么算?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 03:26:33

matlab a=[pi/6 pi/4;pi/3 3*pi/4]; funm(a,'sin') ans= 0.1864 0.0764 0.1018 0.3646 怎么算?
matlab a=[pi/6 pi/4;pi/3 3*pi/4]; funm(a,'sin') ans= 0.1864 0.0764 0.1018 0.3646 怎么算?

matlab a=[pi/6 pi/4;pi/3 3*pi/4]; funm(a,'sin') ans= 0.1864 0.0764 0.1018 0.3646 怎么算?
[4cos 2;(-15π/4+4π)]/[tan(-11π/3+4π)+√2sin(25π/4-6[4cos2(-15pi/4)]/[tan(-11pi/3)+(根号2)*sin(25pi/4)]的值为

matlab a=[pi/6 pi/4;pi/3 3*pi/4]; funm(a,'sin') ans= 0.1864 0.0764 0.1018 0.3646 怎么算? 解方程:sin(2*a)/pi+(pi-a)/pi=0.8,最好能给出matlab程序. 求大神解答一下我这MATLAB程序哪里有问题x=[0:0.01:1]b=[(2*pi)/45,pi/18,pi/12,pi/6,pi/3,pi/2,(2*pi)/3]a=1./(.4*tan(b./2))y=a.*x.^2plot(x,y) matlab中画三维离散点,参数s是关于点的变量,想利用colorbar实现每个点的颜色对应a的值,即4维图x=[];y=[];z=[];s=[];for a1=2/3*pi:pi/20:17/12*pi;for a2=-7/6*pi:pi/20:-1/2*pi;for a3=-1/6*pi:pi/20:2/3*pi;b1=cos(a1)*cos(a2)*cos 怎么用matlab解方程组 a+b=(pi)/2,a*x+b*y=(pi)^2/8,a*x^2+b*y^2=(pi)^3/24,a*x^3+b*y^3=(pi)^4/64 sin(PI/2+a)=-4/5 a属于(Pi,3pi/2)则cos(Pi/3-a)为 1,已知sin(a-pi/3)=1/3,则cos(pi/6+a)= 2,cos29pi/6= 3,cos(pi+a)=-1/3,则(sin2pi/3-a)= 急4,sin(2pi+a)/cos(pi+a)=-3,求(2cos(pi-a)-3sin(pi+a))/(4cos(-a)+sin(2pi-a))的值尽量过程 matlab中t=(0:a)/a*2*pi是什么意思? 求pi问题c语言#include#includevoid main(){ int a, b ; double pi=0; for(a=1, b=3;fabs(pi)>1e-6;a=a+4, b=b+4) { pi = pi + (1/a + 1/b); } pi = pi * 4; printf(%10.6lf, pi); getchar(); } 已知sin(a+pi/3)=4/5且pi/6 matlab解方程2*pi*x=9.8*16*tanh((6*pi)/x)? matlab 构造向量x=0:pi/10:2*pi matlab中X=6*pi*(rand(20,10)-0, Error:Unexpected MATLAB operator.clear all;t=[pi/2:pi/5:5*pi/2];ti=[pi/2:pi/20:5*pi/2];d=[0.209 0.157 0.055 0.009 -0.187 -0.251 -0.192 -0.017 0.060 0.118 0.209];di=-0.0005245*ti.^8+0.01996*ti.^7-0.3211*ti.^6+2.84*ti.^5-15.05*ti.^4+48.81*ti.^3-94.34*t matlab的solve用法定义syms x y a1 a2equ1=1/120 - ((2*a2)/81 + (pi*a1)/12 + pi^2*(a2/405 + 1/12) + (pi^3*a1)/120)/pi^4equ2=-(a2/128 + (2*pi*a1)/81 + pi^2*(a2/960 + 2/81) + (pi^3*a1)/405 - pi^4/405)/pi^5输入solve('方程1', '方程2', 'a1', 'a1') cosa=2/3 a是第四象限角求sin(a-2Pi)+sin(-a-3Pi)cos(a-3Pi)/cos(Pi-a)-cos(-Pi-a)cos(a-4Pi) matlab如何构造一个含变量的矩阵比如有一个矩阵T=[cosa,-sinacosb,sinasinb;sina,cosacosb,-cosasinb;0,sinb,cosb]里面的a=0:pi/36;pi;b=0:pi/36;pi;怎么去构造这个T矩阵呢?打错了,应该是a=0:pi/36:pi;b=0:pi/36:pi matlab中is not a valid expression or equation.x=solve('2/3*14.3*pi*500^3*(sin(x*pi))^3/pi-(sin(pi*x)+sin((1.25-2*x)*pi))*450*x*14.3*pi*500^2*(1-sin(2*pi*x)/(2*pi*x))/(pi*(3x-1.25))=402.86','x')Error using ==> solve' 2/3*14.3*pi*500^3*(sin(x*pi))^3