作业帮若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10你答案算错了应该选D
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若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10你答案算错了应该选D
若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为
A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10
你答案算错了应该选D
若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10你答案算错了应该选D
tana+1/tana=sina/cosa+cosa/sina=[(sina)^2+(cosa)^2]/sinacosa=1/[1/2*2sinacos]
=2/sin2a=10/3
sin2a=3/5
π/4
所以cos2a<0
因为(sin2a)^2+(cos2a)^2=1
所以cos2a=-4/5
sin(2a+π/2)=cos2a=-4/5
已知3π/4小于a小于π,tana+1/tana=-10/3,求tana,
已知3π/4＜a＜π ,tana+1/tana=-10/3 则tana=
tan²a-2tana-3=0.tana=3或tana=-1
1+tanA/1-tanA=3+2.828 tanA=
1+tana/1-tana=-3
若COSa=-3/5,且tana>0,则(tana.cos^3a)/(1-sina)=
若tana＋1/tana－1=3且a为锐角,则sina=?
若1-tanA / 1+tanA=2+√3,则cot(45°+A）等于?
若1-tanA/1+tanA=2+√3,cot(4/π+A)＝
已知tan 3a = 3tana - (tana)^3 / 1-3 (tana)^2 求最小正a使tan3a=1/tana
若锐角A满足tanA+1/(tanA)=3,则tan^2A+1/(tan^2A)=?
tanA=-1,A=?
sin^2A+cos^2A/sinAcosA=-10/3怎么得到 tanA+1/tanA=-10/3
怎么证tan(45+a)=(1+tana)/(1-tana).
求证tan(a+π/4)=(1+tana)/(1-tana)
tan(a+b)-1/tana=2*tana 请化简!
求证tan(A/2)-{1/(tanA/2)}=-2/tanA
求证tan(a/2)-1/(tana/2)=-2/tana