求化简(x+3y+2z)(x-3y+6z)(x+3y+4z-2z)(x-3y+4z+2z)

求化简(x+3y+2z)(x-3y+6z)(x+3y+4z-2z)(x-3y+4z+2z) 2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算 x+y+z=6 x+2y+3z=14 y+1=z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 2x-{3z-[3x-2(z-y)-(x+8y-6z)]} 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 2(x+y)(x+y-z)+3(y-z)(x+y-z) 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, 3x-y+z=4,2z+3y-z=12,x+y+z=6的解 (x-3y+2z)(x+3y-2z) （x-2y+3z)(x+2y-3z) (2y-x-3z)(-x-2y-3z) 证明 ：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z} (x+3y-2z)(x-3y-2z)-(x+3y-2z)^2 x/2=y/3=z/5 x+3y-z/x-3y+z x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27