log4^27×log(8)25×log9^5
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/08 18:10:36
log4^27×log(8)25×log9^5
log4^27×log(8)25×log9^5
log4^27×log(8)25×log9^5
原式=log4 27*log8 25* log9 5
=lg27/lg4*lg25/lg8*lg5/lg9
=3lg3/2lg2*2lg5/3lg2*lg5/2log3
=1/2*(lg5/lg2)^2=1/2*(log2 5)^2
log4^27×log(8)25×log9^5
log4^27×log(8)25×log9^5
(log(2)125+log(2)25+log(8)5)*(log(125)2+log(25)4+log(5)8)
log (log2)^2 - (log4)(log20) + (log20)^2
log
log
log
求值:-log2log2√√√2 ,log4 (8)-log1/9 (3)-log√2 (4) ; (log4(3))*(log9(25))*(log5(8))
log√3^9+log9^27+(1/4)log4^1/16
log√3^9+log9^27+(1/4)log4^1/16
log的计算log2为底 20-log4为底 25
log3 4×log4 8×log8 a=log根号3 9,则a=
log4 8-log1/9 3=log 根号2 1/4怎么算
log(8)9-log(27)32的值,
求log(8)9-log(27)32的值,
已知log(8)27=a,求log(6)16
计算:8^(1-log(83))(27^(2/3))-log(32)
log(2)1/25乘以log(3)1/8乘以log(5)1/9