化简999...9*999...9+1999...9
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化简999...9*999...9+1999...9
化简999...9*999...9+1999...9
化简999...9*999...9+1999...9
原式=999...9*999...9+1000...0+999...9(9、0都为n个)
=999...9*(999...9+1)+1000...0(同上)
=999...9*1000...0+100...0(同上)
=1000...0*(999...9+1)(同上)
=1000...0(2n个0)
=999...9*999...9+1000...0+999...9(9、0都为n个) =999...9*(999...9+1)+1000...0(同上) =999...9*1000...0+100...0(同上) =1000...0*(999...9+1)(同上) =1000...0(2n个0)
化简999...9*999...9+1999...9
化简999...999(2008个9)*999...999(2008个9)+199...999(2008个9)
999.
999...9×999...9+1999...9的末尾有多少个0...是1997个9
19+199+1999+...+1 999...99(2003个9)的和是多少?是计算
999...9(1998个9)*999...9(1998个9)+1999...9(1998个9)=?简便计算
计算:999...9(n个9)*999...9(n个9)+1999...9(n个9)
999...9×999...9+1999...9的末尾有多少个0第一个999...9有200个9,第二个999...9也有200个9,第三个1999...9不看1,也有200个9
999...98(1997个9)*999...98(1997个9)+999...98(1997个9)*2的末尾有多少个0
求这算式的解法:999...9(2000个9)乘999...96(1999个9)=
98+998+9998+...+999...98(50个9)
计算:999...99*999...99+1999...99;(9的个数是2001个)答案和算式
999...9(1997个9)*999...9(1997个9)+1999...9(1997个9)的末尾有多少个零?
999...99(有1997个9)*999...9(有1997个9)+1999...99(有1997个9)的末尾有( )0
黄金999.
化简999...9*999...9+199...9 n个9 n个9 n个9
999...99(2006个9)乘99...97(2005个9)
用含n的代数式表示999..9(n个9)