已知01.比较log a 1/b,log a b,log b 1/b的大小.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 21:55:38
已知01.比较log a 1/b,log a b,log b 1/b的大小.
已知01.比较log a 1/b,log a b,log b 1/b的大小.
已知01.比较log a 1/b,log a b,log b 1/b的大小.
发了图片,最快回答,
画出log的函数图,由a,b的值画出大致区间就可以看出来了。
已知01.比较log a 1/b,log a b,log b 1/b的大小.
已知01比较log(a)(1/b),log(a)(b),log(b)(1/b)的大小
若a²>b>a>1,试比较log b b/a ,log b a,log a b的大小
已知a<b<1,log(a)b+log(b)a=10/3,求log(a)b-log(b)a的值括号为下标,
27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是:()?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了:a=(1/2)^(ln2)log
已知01,则下列不等式中成立的是( )A.log(b)(1/b)<log(a)(b)<log(a)(1/b)B.log(a)(b)<log(b)(1/b)<log(a)(1/b)C.log(a)(b)<log(a)(1/b)<log(b)(1/b)D.log(b)(1/b)<log(a)(1/b)<log(a)(b)
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
1≤a≤b≤c,证明log(a)(b)+log(b)(c)+log(c)(a)≤log(b)(a)+log(c)(b)+log(a)(c)
已知 log (a) ab=1/p ,则 log (ab) a/b=__ __.
化简log(1/a)b+log(a)b
已知log a x=2,log b x=1,log c x=4,求log abc x 的值
已知log(a)x=1,log(b)x=2,log(c)x=4,则log(abc)x=?
已知a=0.2^0.3,b=log(0.2)3,c=log(0.2)4,比较大小
Log(2)1/25•log(3)1/8•log(5)1/9化简 还有已知log(18)9=a,log(18)5=b求log(36)45 值
2^a=log(1/2)a,(1/2)^b=log(1/2)b,(1/2)^c=log(2)c,比较a,b,c的大小
求证 log(a)^(b)=1/log(b)^(a)求证 log(a)^(b)=1/log(b)^(a)
已知0<a<1,x=log a 根号2+log a 根号3y=1/2 log a 5z=log a 根号21 -log a 根号3比较x y z 的大小关系x=log a (根号2)+log a (根号3)y=1/2 (log a 5)z=log a (根号21) -log a (根号3)