f(x)=2cosx sin(x+兀/3)-√3/2化简

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f(x)=2cosx sin(x+兀/3)-√3/2化简
f(x)=2cosx sin(x+兀/3)-√3/2
化简

f(x)=2cosx sin(x+兀/3)-√3/2化简
f(x)=2cosxsinxcos兀/3+2cosxcoxsin兀/3-√3/2
=cosxsinx+√3(cosx)^2-√3/2
=1/2sin2x+√3/2(cos2x+1)-√3/2
=1/2sin2x+√3/2cos2x
=sin(2x+兀/3)

我高二居然不会- =

=2cosx(sinx*0.5+cosx*√3/2)-√3/2
=0.5*sin2x+ √3(cosx)^2- √3/2
=0.5*(sin2x+ √3cos2x)
=sin(2x+兀/3)

f(x)=2cosxsinxcosπ/3+2cosxcosxsinπ/3-sinπ/3
=sin2x/2+√3(1+cos2x)/2-√3/2
=sin2x/2+√3/2cos2x
=sin(2x+π/3)
楼主加个分呀,谢了