计算:(1)(-x^k-1)^2= (2)(-3x^3)^2-[(2x)^2]^3 (3)-0.125^6*2^6*4^6=(4)[a^3)^3·(-a^4)^3]/(a^2)^3/(a^4)^2=(5)(a-b)^5·(a-b)^6+(a-b)^21/(a-b)^10=
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 10:31:06
计算:(1)(-x^k-1)^2= (2)(-3x^3)^2-[(2x)^2]^3 (3)-0.125^6*2^6*4^6=(4)[a^3)^3·(-a^4)^3]/(a^2)^3/(a^4)^2=(5)(a-b)^5·(a-b)^6+(a-b)^21/(a-b)^10=
计算:(1)(-x^k-1)^2= (2)(-3x^3)^2-[(2x)^2]^3 (3)-0.125^6*2^6*4^6=
(4)[a^3)^3·(-a^4)^3]/(a^2)^3/(a^4)^2=
(5)(a-b)^5·(a-b)^6+(a-b)^21/(a-b)^10=
计算:(1)(-x^k-1)^2= (2)(-3x^3)^2-[(2x)^2]^3 (3)-0.125^6*2^6*4^6=(4)[a^3)^3·(-a^4)^3]/(a^2)^3/(a^4)^2=(5)(a-b)^5·(a-b)^6+(a-b)^21/(a-b)^10=
:(1)(-x^k-1)^2= x^(2k-2)
(2)(-3x^3)^2-[(2x)^2]^3=9x^6-8x^6=x^6
(3)-0.125^6*2^6*4^6==-(0.125×2×4)^6=-1
(4)[a^3)^3·(-a^4)^3]/(a^2)^3/(a^4)^2=-a^9a^12÷a^6÷a^8=-a^7
(5)(a-b)^5·(a-b)^6+(a-b)^21/(a-b)^10=(a-b)^11+(a-b)^11=2(a-b)^11
(1)=x^2k-2
(2)=9x^6-(2x)^6=9x^6-64x^6=-55x^6
(3)=-(1/8)^6*2^6*4^6=-1^6=-1
(4)=【a^9*(-a^12)】/a^6/a^8=-a^21/a^14=-a^7
(5)=(a-b)^11+(a-b)^11=2(a-b)^11