log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
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log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
log4(sin3π/4) + log9[tan(-5π/6)]
=log4 (√2/2) + log9 [-tan(5π/6)]
=log4 (√2/2) + log9 [-(-√3/3)]
=log4 (√2/2) + log9 (√3/3)
=log(2^2) [2^(-1/2)] + log(3^2) [(3)^(-1/2)]
=[(-1/2)/2]log2 2 + [(-1/2)/2]log3 3
=-1/4 - 1/4
=-1/2
=log4 (√2/2) + log9 (√3/3)
=log4[4^(-1/4)]+log9[3^(-1/4)]
=-1/4-1/4
=-1/2
log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
log9×log4
LOG4 SIN3/4π+LOG3 tan(-5/6π)=?
log4 sin(3π)/4+log9 tan[(-5π)/6]=_______.
log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27)
(log3^2 + log9^4)×(log4^3 + log8^3)
log2^根号下2+log9^27+4^(log4^13)
log2 根号2+log9 27+4^log4 13=?
计算:(1/4)^log4^1/3-lg25-lg4-log9^27
计算log4(3)*log9(32)
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
log4³×log9²+以4为底4次根号下对数
如题{log(2√2) - 3log√3 - 3} / {log9 - log4 + 4}
若log2^3×log3^4×log4^x=log9^3 ,求x
对数函数计算 log4 3·log9 2-log1/2 4次根号32
各位大神log4(3)log9(2)-log1/2(4√32)怎做啊?是不是?
log√3^9+log9^27+(1/4)log4^1/16
log2 √2 +log9 27 +4∧log4 13的值为