3m^3 n-6m^2 n^2-72mn^3 十字相乘法解
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3m^3 n-6m^2 n^2-72mn^3 十字相乘法解
3m^3 n-6m^2 n^2-72mn^3 十字相乘法解
3m^3 n-6m^2 n^2-72mn^3 十字相乘法解
3m^3 n-6m^2 n^2-72mn^3
=3mn(m²-2mn-24n²)
=3mn(m-6n)(m+4n)
m-n=7 mn=-5求(3m+5n+4mn)-(2n-4n+6mn)
1/M+1/N=5 (3M+MN+2N) / (M-MN=3N)
计算:[-m^3n/(m-n)^2]^4*[(n^2-mn)/m]^3/m^4n^10*[(mn-n^2)/m]^6
(5mn-2m+3n)+(-7m-7mn)
(5mn-2m+3n)+(-7m-7mn)
m^3n-2m^2n^2+mn^3
m²-3mn+2n²+m-n因式分解
因式分解:8mn(n-m)+2(n-m)^3
因式分解:8mn(n-m)+2(n-m)^3,
若(m+n)^2-mn(m+n)=(m+n)·M,则M是() A.m^2+n^2 B.m^2-mn+n^2 C.m^2-3mn+n^2 D.m^2+mn+n^2
已知MN^2=-6,求-MN(M^2N^5-MN^3-N)的值
(m-n)(m^5+m^4n+m^3n^2+m²n^3+mn^4+n^5)
3m^3 n-6m^2 n^2-72mn^3 十字相乘法解
(m^2-n^2/mn)^2÷(m+n)^2*(m/m-n)^3 化简
急2[mn+(-3m)]-3(2n-mn),m+n=2 mn=-3
3(m^2n+mn)-4(mn-2m^2n)+mn.要有过程
已知m-n=4,m、n互为倒数求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4m+mn)的值
m+n=5,mn=14,则(3m-2n)-(-5n+mn)