(sina+sinb)^2+(cosa+cosb)^2=?A.(COS(a-b)/2)^2B.4(COS(a-b)/2)^2C..(sin(a-b)/2)^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 23:30:12
(sina+sinb)^2+(cosa+cosb)^2=?A.(COS(a-b)/2)^2B.4(COS(a-b)/2)^2C..(sin(a-b)/2)^2
(sina+sinb)^2+(cosa+cosb)^2=?
A.(COS(a-b)/2)^2
B.4(COS(a-b)/2)^2
C..(sin(a-b)/2)^2
(sina+sinb)^2+(cosa+cosb)^2=?A.(COS(a-b)/2)^2B.4(COS(a-b)/2)^2C..(sin(a-b)/2)^2
(sina+sinb)^2+(cosa+cosb)^2
=sin²a+2sina*sinb+sin²b+cos²a+2cosa*cosb+cos²b
=2+2(sina*sinb+cosa*cosb)
=2+2cos(a-b)
展开=1+1+2(sinasinb+cosacosb)=2+2cos(a-b)
sinA+sinB sinA-sinB cosA+cosB cosA-cosB
sinA/sinB=cosB/cosA
(sina-cosa)(sinb-cosb)化简
(cosa)^2(cosb)^2-(sina)^2(sinb)^2.为什么等于.(cosa)^2-(sinb)^2
求证:sina^2+sinb^2-sina^2*sinb^2+cosa^2*cosb^2=1
化简:sina^2+sinb^2-sina^2sinb^2+cosa^2cosb^2
(1+sina-cosa)/sina * (1+sinb-cosb) /sinb=2,求tana*tanba,b是锐角.
求证:cosa(cosa-cosb)+sina(sina-sinb)=2sin^2a-b/2
sina+2sinb,tana=3tanb,则cosa=
判断三角形形状:(SINA+SINB)(COSA+COSB)=2SINC
求证:sina+sinb/(cosa+cosb)=tan[(a+b)/2]
已知sina=2sinb.tana=3tanb,cosa
sina+cosa=1/2,sinb-cosb=1/3
SinA=2SinB TanA=3TanB CosA=?
三角恒等公式cosa cosb sina cosb - cosa cosb cosa sinb - sina sinb sina cosb + sina sinb cosa sinb 约成最简 在解释一下恒等公式sina + sinb
已知sinA+cosA=2sina,sinA*cosA=(sinb)^2,求证4(cos2a)^2=(cos2b)^2
已知sinA+cosA=2sina,sinA*cosA=(sinb)^2,求证4(sin2a)^2=(cos2b)^2
(sinA+cosA)的平方=2(sinB+1/sinB),求A+B