main(){ int x=5; while(x

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main(){ int x=5; while(x
main(){ int x=5; while(x

main(){ int x=5; while(x
x自加到12的时候,if(x%3==0)满足,就break跳出while循环了,不会继续往下自加了.所以13,14,15,16这几个值x都走不到.

main(){ int x=5; while(x #include main() { int x=3,y; do { y=x--; if(!y) {printf(*);continue;} printf(#); }whi下面程序段____________#include main(){int x=3,y;do{y=x--;if(!y){printf(*);continue;}printf(#);}while(1 void main() { int x=0,y=5,z=3; while(z-->0&&++x 这段程序为什么无法输出结果呢?main(){int x=5;printf(%f,x);} #include main() { int x=0; while(x++ main(){int x,i;for(i=1;i #include int main(){ int x=0,y=0; while(x #include void main( ) { int a=3,b=5; int *p,*q; void f1(int x,int y);void f2(int *x,int *y);p=&a; q=&b;f1(*p,*q) ;printf(a=%d ,b=%d ,a,b);f2(p,q);printf(a=%d ,b=%d ,a,b);}void f1(int x,int y) { int t;t=x; x=y; y=t;}void f2(int *x,int *y) { int void main() {int x=4;if(x++>=5)printf(%d/n,x);else printf(%d/n,x--); C语言问题int x=3;incre();main(){ int i; for (i=1;i int x=3;main(){int i;for(i=1;i int x=3;main(){int i;for(i=1;i 7、交换两个整数 int main( ) { int x(5) , y(10) ; cout fun(int x,int y,int z) {z=x*x+y*y;} main() {int a=31; fun(5,2,a); printf(%d,a); } a的值为多少?是29还是31?说明一下理由, #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf(a=%d,x=%d ,a, #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf(a=%d,x=%d ,a, 以下程序输出的结果是 main() {int x; x=-3+4%6/5; printf(%d,x); } void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){ int *c; c=a;a=b;b=c;}main(){ int x=3,y=5,*p=&x,*q=&y; fun(p,q); printf(%d,%d,,*p,*q); fun(&x,&y); prin%d,%d ,*p,*q);}两