帮我解一个二元二次的符号方程组-9*x1^2-6*x1*x2+3*x2^2+(12*e1-24)*x1-4*e1^2-12*e1-12+3*k=0-3*x1^2+6*x1*x2+9*x2^2-(12*e1+72)*x2+4*e1^2+36*e1+108+3*k=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 13:20:31

帮我解一个二元二次的符号方程组-9*x1^2-6*x1*x2+3*x2^2+(12*e1-24)*x1-4*e1^2-12*e1-12+3*k=0-3*x1^2+6*x1*x2+9*x2^2-(12*e1+72)*x2+4*e1^2+36*e1+108+3*k=0
帮我解一个二元二次的符号方程组
-9*x1^2-6*x1*x2+3*x2^2+(12*e1-24)*x1-4*e1^2-12*e1-12+3*k=0
-3*x1^2+6*x1*x2+9*x2^2-(12*e1+72)*x2+4*e1^2+36*e1+108+3*k=0

帮我解一个二元二次的符号方程组-9*x1^2-6*x1*x2+3*x2^2+(12*e1-24)*x1-4*e1^2-12*e1-12+3*k=0-3*x1^2+6*x1*x2+9*x2^2-(12*e1+72)*x2+4*e1^2+36*e1+108+3*k=0
这组方程看不懂那 没办法帮你解

x1=(144*e1 - 42*k - (1440*(3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3))/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/1...

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x1=(144*e1 - 42*k - (1440*(3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3))/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) - 192*((7*e1)/12 - (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + ((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + e1^2/144 + 8/3)^2 + 3*e1*k + 1440*((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + 228*e1*((7*e1)/12 - (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + ((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + e1^2/144 + 8/3) - 3*k*((7*e1)/12 - (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + ((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + e1^2/144 + 8/3) - 74*e1^2 + 2*e1^2*((7*e1)/12 - (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + ((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + e1^2/144 + 8/3) + 1728)/(2*e1^2 + 12*e1 + 3*k + 288);
x2=(7*e1)/12 - (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)/((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + ((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + (((41*e1)/8 + (3*k)/16 + (7*e1*k)/64 + (e1^2*k)/384 + (e1^2/48 + (7*e1)/4 + 8)^3/27 + (17*e1^2)/12 + (5*e1^3)/32 + e1^4/288 + k^2/512 - ((e1^2/48 + (7*e1)/4 + 8)*(e1^3/48 + (29*e1^2)/24 + 9*e1 + (3*k)/8 + 17))/6 + 5)^2 + (3*e1 + k/8 - (e1^2/48 + (7*e1)/4 + 8)^2/9 + (29*e1^2)/72 + e1^3/144 + 17/3)^3)^(1/2) + 5)^(1/3) + e1^2/144 + 8/3;
答案就写了两个,太长了写不下。我是用matlab软件求解的。希望你能满意!

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帮我解一个二元二次的符号方程组-9*x1^2-6*x1*x2+3*x2^2+(12*e1-24)*x1-4*e1^2-12*e1-12+3*k=0-3*x1^2+6*x1*x2+9*x2^2-(12*e1+72)*x2+4*e1^2+36*e1+108+3*k=0 谁帮我解一下下面的二元二次的方程组 设计一个用二元二次方程和二元一次方程组成的二元二次方程组.解为:x1=2,y1=4,x2=-2,y2=-4 一个二元一次方程和一个二元二次方程组成的二元二次方程组的解是X1=1,Y1=2,X2=-1,Y2=-2,试写出一个符合要求的方程组 有一个二元一次方程和二元二次方程组成的二元二次方程组的解是 x1=-1 x2=-3,y1=-3 y2=-1试写出一个符合要求的方程组 数学题二元二次方程请你构造一个由一个二元一次方程和一个二元二次方程组成的二元二次方程组并使它的解为x1=2,y1=4、、x2=-2,y2=-4 关于二元二次方程组的解与方程组的关系已知由一个二元一次方程和一个二元二次方程组成的二元二次方程组的解是x1=1 y1=2 和x2=-1 y2=-2,你能写出一个这样的方程吗? 写出一个二元二次方程组,使它的解为{x1=2 y2=3 和 X2=-2 y2=-3 帮我解一下下面那道二元二次方程组.谢谢···· 二元二次方程组的解法 解方程组,二元二次,谢谢! 怎么解二元二次方程组 解一道二元二次方程组, 请设计一个二元二次方程组,使得这个二元二次方程组的解是(x=2 y=3)和(x=-4 y=-2 请设计一个二元二次方程组,使得这个二元二次方程组的解是(x=2 y=3)和(x=-4 y=-2 解方程组 初二二元二次方程组 关于二元二次方程组.二元二次方程组的解就是方程组中两个方程的解的____. 解一解这个二元二次方程组,我不知道怎么解这样的方程组,求解题的方法.