[(x+y)平方-y(2x+y)-8x]除以2x
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[(x+y)平方-y(2x+y)-8x]除以2x
[(x+y)平方-y(2x+y)-8x]除以2x
[(x+y)平方-y(2x+y)-8x]除以2x
乘出来
(x^2+2xy+y^2-2xy-y^2-8x)÷2x
=(x^2-8x)÷2x
=x^2÷2x-8x÷2x
=x/2-4
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