已知x>0,y>0,且x-2√xy-15y=0,求(2x+√xy+3y)÷(x+√xy-y)的值求过程~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

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已知x>0,y>0,且x-2√xy-15y=0,求(2x+√xy+3y)÷(x+√xy-y)的值求过程~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
已知x>0,y>0,且x-2√xy-15y=0,求(2x+√xy+3y)÷(x+√xy-y)的值
求过程~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

已知x>0,y>0,且x-2√xy-15y=0,求(2x+√xy+3y)÷(x+√xy-y)的值求过程~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x-2√xy-15y=0
(√x)²-2√xy-15(√y)²=
(√x+3√y)(√x-5√y)=0
∴√x=5√y
x=25y
(2x+√xy+3y)÷(x+√xy-y)
=(50y+5y+3y)÷(25y+5y-y)
=2

因为X>0,y>0,x-2√xy-15y=0,所以得,(√X+3√y)(√x-5√y)=0,√x+3√y=0(舍去),√x-5√y=0,即√x=5√y,代入原式的=(50y+5√y√y+3y)÷(25y+5√y√y-y)=2