(a^2bc)^4/(ab^2c)^3·(abc)^2 急!

(a^2bc)^4/(ab^2c)^3·(abc)^2 急!
(a^2bc)^4/(ab^2c)^3·(abc)^2 急!

(a^2bc)^4/(ab^2c)^3·(abc)^2 急!
(a^2bc)^4/(ab^2c)^3·(abc)^2
=a^8b^4c^4÷(a^3b^6c^3)*(a^2b^2c^2)
=a^(8-3+2)b^(4-6+2)c^(4-3+2)
=a^7c^3

(a^2bc)^4/[(ab^2c)^3(abc)^2]
＝a^8b^4c^4/a^5b^8c^5
＝a^3/b^4c