作业帮化简求值cos(-11π/3)=_,tan(-1035°)=_
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化简求值cos(-11π/3)=_,tan(-1035°)=_
化简求值cos(-11π/3)=_,tan(-1035°)=_
化简求值cos(-11π/3)=_,tan(-1035°)=_
cos(-11兀/3+4兀)=cos(兀/3)=0.5
tan(-1035°)=tan(-3x360°+45)=tan45°=1
cos(-11π/3)=1/2 tan(-1035°)=tan(-3x360°+45)=tan45°=1
化简求值cos(-11π/3)=_,tan(-1035°)=_
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