f(x)=2sin(x/4)cos(x/4)-2根号3*sin²(x/4)+根号3 求1.当x∈[0,π],求f(x)值域2.f(x)单调递增区间

f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x) f(x)=sin(x+π/4)图像怎样变成F(x)=cos(2x) f(x)=cos(2x)+2sin(x)化简 f'(sin^2x)=cos^2x,求f(x)f'((sin^x)^2)=(cos^x)^2 f(x)为奇函数,x>0,f(x)=sin 2x+cos x,则x 已知f(x)=cos^2x/1+sin^2x求f'(π/4)求导 证明∫( 0,π／2 ) (f sin x/(f sin x+f cos x) dx=π /4 已知f(x)=cos(x/2)[sin(x/2)-cos(x/2)],其导为? f(x)=cos(2兀-x)cos(2/兀-x)-sin方x化简速求 f(sin x)=3-cos 2x,求f(cos x)=? 设f(sin x)=3-cos 2x,则f(cos x）=? 若F(sin x)=3-cos 2x 则F（cos x）=? f'(sin x)=1-cos x 求f''(x) 化简：f(x)=sin(x)cos(x)/sin(2x) f(sin x)=cos 2x +1 求 f(cos x) f(sin x)=3-cos 2x求f(cos x) f(cos x)=2-sin 2x,则f(sin x)=? f(x)=2sin^2(π/4+x)+根号3(sin^2x+cos^2x)f(x)=2sin^2(π/4+x)+根号3(sin^2x-cos^2x) 符号打错了