1.等差数列{an},{bn}的前n项和分别为Sn,Tn,(1)若Sm=n,Sn=m,求Sn+m(2)若Sn/Tn=(7n+1)/(4n+27),求an/bn2.已知等差数列{an}中,公差d>0,其前n项和为Sn,且满足a2xa3=45,a1+a4=14,(1)通过bn=Sn/(n+c)构造一个新的数列{
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1.等差数列{an},{bn}的前n项和分别为Sn,Tn,(1)若Sm=n,Sn=m,求Sn+m(2)若Sn/Tn=(7n+1)/(4n+27),求an/bn2.已知等差数列{an}中,公差d>0,其前n项和为Sn,且满足a2xa3=45,a1+a4=14,(1)通过bn=Sn/(n+c)构造一个新的数列{
1.等差数列{an},{bn}的前n项和分别为Sn,Tn,(1)若Sm=n,Sn=m,求Sn+m
(2)若Sn/Tn=(7n+1)/(4n+27),求an/bn
2.已知等差数列{an}中,公差d>0,其前n项和为Sn,且满足a2xa3=45,a1+a4=14,(1)通过bn=Sn/(n+c)构造一个新的数列{bn},是否存在一个非零常数c,使{bn}也为等差数列(2)在(1)的条件下,求f(n)=bn/((n+2005)xbn+1)的最大值,n+1是下标
1.等差数列{an},{bn}的前n项和分别为Sn,Tn,(1)若Sm=n,Sn=m,求Sn+m(2)若Sn/Tn=(7n+1)/(4n+27),求an/bn2.已知等差数列{an}中,公差d>0,其前n项和为Sn,且满足a2xa3=45,a1+a4=14,(1)通过bn=Sn/(n+c)构造一个新的数列{
a2xa3=45,a1+a4=a2+a3=14,a2
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