若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值

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若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值

若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
∵2m=3n
∴m/n=3/2
令 m=3k n=2k (k≠0)
那么
[1+m/n-n/(n-m)]/[1-m/n-n/(n+m)]
=(1+3/2+2)/(1-3/2-2/5)
=(9/2)/(9/10)
=5